2d^2+10d-600=0

Solution for 2d^2+10d-600=0 equation:

2d^2+10d-600=0

a = 2; b = 10; c = -600;
Δ = b2-4ac
Δ = 102-4·2·(-600)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-70}{2*2}=\frac{-80}{4}
=-20
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+70}{2*2}=\frac{60}{4}
=15
$